在对数据库数据进行处理的时候,因程序设计需要对数据库中重复的记录进行查询,相信这个问题很多人都有遇到过,在这里微思考整理了一下关于这方面的内容,供大家参考
说到SQL查询重复记录,我们先来认识一下SQL HAVING 子句,在 SQL 中增加 HAVING 子句原因是,WHERE 关键字无法与合计函数一起使用。
having是分组(group by)后的筛选条件,分组后的数据组内再筛选,where则是在分组前筛选
SQL HAVING 语法
SELECT column_name, aggregate_function(column_name) FROM table_name WHERE column_name operator value GROUP BY column_name HAVING aggregate_function(column_name) operator value
SQL HAVING 实例
我们拥有下面这个 "Orders" 表:
O_Id | OrderDate | OrderPrice | Customer |
---|---|---|---|
1 | 2008/12/29 | 1000 | Bush |
2 | 2008/11/23 | 1600 | Carter |
3 | 2008/10/05 | 700 | Bush |
4 | 2008/09/28 | 300 | Bush |
5 | 2008/08/06 | 2000 | Adams |
6 | 2008/07/21 | 100 | Carter |
现在,我们希望查找订单总金额少于 2000 的客户。
我们使用如下 SQL 语句:
SELECT Customer,SUM(OrderPrice) FROM Orders GROUP BY Customer HAVING SUM(OrderPrice)<2000
结果集类似:
Customer | SUM(OrderPrice) |
---|---|
Carter | 1700 |
现在我们希望查找客户 "Bush" 或 "Adams" 拥有超过 1500 的订单总金额。
我们在 SQL 语句中增加了一个普通的 WHERE 子句:
SELECT Customer,SUM(OrderPrice) FROM Orders WHERE Customer='Bush' OR Customer='Adams' GROUP BY Customer HAVING SUM(OrderPrice)>1500
结果集:
Customer | SUM(OrderPrice) |
---|---|
Bush | 2000 |
Adams | 2000 |
介绍完having,进入正题---SQL重复记录查询的几种方法
查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断
select * from people
where peopleId in (select peopleId from people group by peopleId having count
(peopleId) > 1)
删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录
delete from people
where peopleId in (select peopleId from people group by peopleId having count
(peopleId) > 1)
and rowid not in (select min(rowid) from people group by peopleId having count(peopleId
)>1)
查找表中多余的重复记录(多个字段)
select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having
count(*) > 1)
删除表中多余的重复记录(多个字段),只留有rowid最小的记录
delete from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having
count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
查找表中多余的重复记录(多个字段),不包含rowid最小的记录
select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having
count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
示例
显示每个地区的总人口数和总面积.仅显示那些面积超过1000000的地区。
SELECT region, SUM(population), SUM(area)7
FROM bbc
GROUP BY region
HAVING SUM(area)>1000000
在这里,我们不能用where来筛选超过1000000的地区,因为表中不存在这样一条记录。
相反,HAVING子句可以让我们筛选成组后的各组数据
SQL SELECT DISTINCT 语句
在表中,可能会包含重复值。这并不成问题,不过,有时您也许希望仅仅列出不同(distinct)的值。
关键词 DISTINCT 用于返回唯一不同的值。
语法:
SELECT DISTINCT 列名称 FROM 表名称
使用 DISTINCT 关键词
如果要从 "Company" 列中选取所有的值,我们需要使用 SELECT 语句:
SELECT Company FROM Orders
"Orders"表:
Company | OrderNumber |
---|---|
IBM | 3532 |
W3School | 2356 |
Apple | 4698 |
W3School | 6953 |
结果:
Company |
---|
IBM |
W3School |
Apple |
W3School |
请注意,在结果集中,W3School 被列出了两次。
如需从 Company" 列中仅选取唯一不同的值,我们需要使用 SELECT DISTINCT 语句:
SELECT DISTINCT Company FROM Orders
结果:
Company |
---|
IBM |
W3School |
Apple |
现在,在结果集中,"W3School" 仅被列出了一次。
有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重 复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略
对于第一种重复,比较容易解决,使用
select distinct * from tableName
就可以得到无重复记录的结果集
如果该表需要删除重复的记录(重复记录保留1条),可以按以下方法删除
select distinct * into #Tmp from tableName
drop table tableName
select * into tableName from #Tmp
drop table #Tmp
第二类重复问题通常要求保留重复记录中的第一条记录,操作方法如下(假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集)
select identity(int,1,1) as autoID, * into #Tmp from tableName
select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID
select * from #Tmp where autoID in(select autoID from #tmp2)
最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写
在select子句中省去此列)
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